Integrand size = 24, antiderivative size = 138 \[ \int \frac {(d+e x)^7}{\left (d^2-e^2 x^2\right )^{7/2}} \, dx=\frac {2 (d+e x)^6}{5 e \left (d^2-e^2 x^2\right )^{5/2}}-\frac {14 (d+e x)^4}{15 e \left (d^2-e^2 x^2\right )^{3/2}}+\frac {14 (d+e x)^2}{3 e \sqrt {d^2-e^2 x^2}}+\frac {7 \sqrt {d^2-e^2 x^2}}{e}-\frac {7 d \arctan \left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )}{e} \]
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Time = 0.04 (sec) , antiderivative size = 138, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {683, 655, 223, 209} \[ \int \frac {(d+e x)^7}{\left (d^2-e^2 x^2\right )^{7/2}} \, dx=-\frac {7 d \arctan \left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )}{e}+\frac {2 (d+e x)^6}{5 e \left (d^2-e^2 x^2\right )^{5/2}}-\frac {14 (d+e x)^4}{15 e \left (d^2-e^2 x^2\right )^{3/2}}+\frac {14 (d+e x)^2}{3 e \sqrt {d^2-e^2 x^2}}+\frac {7 \sqrt {d^2-e^2 x^2}}{e} \]
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Rule 209
Rule 223
Rule 655
Rule 683
Rubi steps \begin{align*} \text {integral}& = \frac {2 (d+e x)^6}{5 e \left (d^2-e^2 x^2\right )^{5/2}}-\frac {7}{5} \int \frac {(d+e x)^5}{\left (d^2-e^2 x^2\right )^{5/2}} \, dx \\ & = \frac {2 (d+e x)^6}{5 e \left (d^2-e^2 x^2\right )^{5/2}}-\frac {14 (d+e x)^4}{15 e \left (d^2-e^2 x^2\right )^{3/2}}+\frac {7}{3} \int \frac {(d+e x)^3}{\left (d^2-e^2 x^2\right )^{3/2}} \, dx \\ & = \frac {2 (d+e x)^6}{5 e \left (d^2-e^2 x^2\right )^{5/2}}-\frac {14 (d+e x)^4}{15 e \left (d^2-e^2 x^2\right )^{3/2}}+\frac {14 (d+e x)^2}{3 e \sqrt {d^2-e^2 x^2}}-7 \int \frac {d+e x}{\sqrt {d^2-e^2 x^2}} \, dx \\ & = \frac {2 (d+e x)^6}{5 e \left (d^2-e^2 x^2\right )^{5/2}}-\frac {14 (d+e x)^4}{15 e \left (d^2-e^2 x^2\right )^{3/2}}+\frac {14 (d+e x)^2}{3 e \sqrt {d^2-e^2 x^2}}+\frac {7 \sqrt {d^2-e^2 x^2}}{e}-(7 d) \int \frac {1}{\sqrt {d^2-e^2 x^2}} \, dx \\ & = \frac {2 (d+e x)^6}{5 e \left (d^2-e^2 x^2\right )^{5/2}}-\frac {14 (d+e x)^4}{15 e \left (d^2-e^2 x^2\right )^{3/2}}+\frac {14 (d+e x)^2}{3 e \sqrt {d^2-e^2 x^2}}+\frac {7 \sqrt {d^2-e^2 x^2}}{e}-(7 d) \text {Subst}\left (\int \frac {1}{1+e^2 x^2} \, dx,x,\frac {x}{\sqrt {d^2-e^2 x^2}}\right ) \\ & = \frac {2 (d+e x)^6}{5 e \left (d^2-e^2 x^2\right )^{5/2}}-\frac {14 (d+e x)^4}{15 e \left (d^2-e^2 x^2\right )^{3/2}}+\frac {14 (d+e x)^2}{3 e \sqrt {d^2-e^2 x^2}}+\frac {7 \sqrt {d^2-e^2 x^2}}{e}-\frac {7 d \tan ^{-1}\left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )}{e} \\ \end{align*}
Time = 0.58 (sec) , antiderivative size = 105, normalized size of antiderivative = 0.76 \[ \int \frac {(d+e x)^7}{\left (d^2-e^2 x^2\right )^{7/2}} \, dx=\frac {\sqrt {d^2-e^2 x^2} \left (-167 d^3+381 d^2 e x-277 d e^2 x^2+15 e^3 x^3\right )}{15 e (-d+e x)^3}+\frac {7 d \log \left (-\sqrt {-e^2} x+\sqrt {d^2-e^2 x^2}\right )}{\sqrt {-e^2}} \]
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Time = 2.50 (sec) , antiderivative size = 192, normalized size of antiderivative = 1.39
method | result | size |
risch | \(\frac {\sqrt {-x^{2} e^{2}+d^{2}}}{e}-\frac {7 d \arctan \left (\frac {\sqrt {e^{2}}\, x}{\sqrt {-x^{2} e^{2}+d^{2}}}\right )}{\sqrt {e^{2}}}-\frac {232 d \sqrt {-\left (x -\frac {d}{e}\right )^{2} e^{2}-2 \left (x -\frac {d}{e}\right ) d e}}{15 e^{2} \left (x -\frac {d}{e}\right )}-\frac {16 d^{3} \sqrt {-\left (x -\frac {d}{e}\right )^{2} e^{2}-2 \left (x -\frac {d}{e}\right ) d e}}{5 e^{4} \left (x -\frac {d}{e}\right )^{3}}-\frac {128 d^{2} \sqrt {-\left (x -\frac {d}{e}\right )^{2} e^{2}-2 \left (x -\frac {d}{e}\right ) d e}}{15 e^{3} \left (x -\frac {d}{e}\right )^{2}}\) | \(192\) |
default | \(d^{7} \left (\frac {x}{5 d^{2} \left (-x^{2} e^{2}+d^{2}\right )^{\frac {5}{2}}}+\frac {\frac {4 x}{15 d^{2} \left (-x^{2} e^{2}+d^{2}\right )^{\frac {3}{2}}}+\frac {8 x}{15 d^{4} \sqrt {-x^{2} e^{2}+d^{2}}}}{d^{2}}\right )+e^{7} \left (-\frac {x^{6}}{e^{2} \left (-x^{2} e^{2}+d^{2}\right )^{\frac {5}{2}}}+\frac {6 d^{2} \left (\frac {x^{4}}{e^{2} \left (-x^{2} e^{2}+d^{2}\right )^{\frac {5}{2}}}-\frac {4 d^{2} \left (\frac {x^{2}}{3 e^{2} \left (-x^{2} e^{2}+d^{2}\right )^{\frac {5}{2}}}-\frac {2 d^{2}}{15 e^{4} \left (-x^{2} e^{2}+d^{2}\right )^{\frac {5}{2}}}\right )}{e^{2}}\right )}{e^{2}}\right )+7 d \,e^{6} \left (\frac {x^{5}}{5 e^{2} \left (-x^{2} e^{2}+d^{2}\right )^{\frac {5}{2}}}-\frac {\frac {x^{3}}{3 e^{2} \left (-x^{2} e^{2}+d^{2}\right )^{\frac {3}{2}}}-\frac {\frac {x}{e^{2} \sqrt {-x^{2} e^{2}+d^{2}}}-\frac {\arctan \left (\frac {\sqrt {e^{2}}\, x}{\sqrt {-x^{2} e^{2}+d^{2}}}\right )}{e^{2} \sqrt {e^{2}}}}{e^{2}}}{e^{2}}\right )+\frac {7 d^{6}}{5 e \left (-x^{2} e^{2}+d^{2}\right )^{\frac {5}{2}}}+21 d^{2} e^{5} \left (\frac {x^{4}}{e^{2} \left (-x^{2} e^{2}+d^{2}\right )^{\frac {5}{2}}}-\frac {4 d^{2} \left (\frac {x^{2}}{3 e^{2} \left (-x^{2} e^{2}+d^{2}\right )^{\frac {5}{2}}}-\frac {2 d^{2}}{15 e^{4} \left (-x^{2} e^{2}+d^{2}\right )^{\frac {5}{2}}}\right )}{e^{2}}\right )+35 d^{3} e^{4} \left (\frac {x^{3}}{2 e^{2} \left (-x^{2} e^{2}+d^{2}\right )^{\frac {5}{2}}}-\frac {3 d^{2} \left (\frac {x}{4 e^{2} \left (-x^{2} e^{2}+d^{2}\right )^{\frac {5}{2}}}-\frac {d^{2} \left (\frac {x}{5 d^{2} \left (-x^{2} e^{2}+d^{2}\right )^{\frac {5}{2}}}+\frac {\frac {4 x}{15 d^{2} \left (-x^{2} e^{2}+d^{2}\right )^{\frac {3}{2}}}+\frac {8 x}{15 d^{4} \sqrt {-x^{2} e^{2}+d^{2}}}}{d^{2}}\right )}{4 e^{2}}\right )}{2 e^{2}}\right )+35 d^{4} e^{3} \left (\frac {x^{2}}{3 e^{2} \left (-x^{2} e^{2}+d^{2}\right )^{\frac {5}{2}}}-\frac {2 d^{2}}{15 e^{4} \left (-x^{2} e^{2}+d^{2}\right )^{\frac {5}{2}}}\right )+21 d^{5} e^{2} \left (\frac {x}{4 e^{2} \left (-x^{2} e^{2}+d^{2}\right )^{\frac {5}{2}}}-\frac {d^{2} \left (\frac {x}{5 d^{2} \left (-x^{2} e^{2}+d^{2}\right )^{\frac {5}{2}}}+\frac {\frac {4 x}{15 d^{2} \left (-x^{2} e^{2}+d^{2}\right )^{\frac {3}{2}}}+\frac {8 x}{15 d^{4} \sqrt {-x^{2} e^{2}+d^{2}}}}{d^{2}}\right )}{4 e^{2}}\right )\) | \(694\) |
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Time = 0.29 (sec) , antiderivative size = 175, normalized size of antiderivative = 1.27 \[ \int \frac {(d+e x)^7}{\left (d^2-e^2 x^2\right )^{7/2}} \, dx=\frac {167 \, d e^{3} x^{3} - 501 \, d^{2} e^{2} x^{2} + 501 \, d^{3} e x - 167 \, d^{4} + 210 \, {\left (d e^{3} x^{3} - 3 \, d^{2} e^{2} x^{2} + 3 \, d^{3} e x - d^{4}\right )} \arctan \left (-\frac {d - \sqrt {-e^{2} x^{2} + d^{2}}}{e x}\right ) + {\left (15 \, e^{3} x^{3} - 277 \, d e^{2} x^{2} + 381 \, d^{2} e x - 167 \, d^{3}\right )} \sqrt {-e^{2} x^{2} + d^{2}}}{15 \, {\left (e^{4} x^{3} - 3 \, d e^{3} x^{2} + 3 \, d^{2} e^{2} x - d^{3} e\right )}} \]
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\[ \int \frac {(d+e x)^7}{\left (d^2-e^2 x^2\right )^{7/2}} \, dx=\int \frac {\left (d + e x\right )^{7}}{\left (- \left (- d + e x\right ) \left (d + e x\right )\right )^{\frac {7}{2}}}\, dx \]
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Leaf count of result is larger than twice the leaf count of optimal. 327 vs. \(2 (122) = 244\).
Time = 0.31 (sec) , antiderivative size = 327, normalized size of antiderivative = 2.37 \[ \int \frac {(d+e x)^7}{\left (d^2-e^2 x^2\right )^{7/2}} \, dx=\frac {7}{15} \, d e^{6} x {\left (\frac {15 \, x^{4}}{{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}} e^{2}} - \frac {20 \, d^{2} x^{2}}{{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}} e^{4}} + \frac {8 \, d^{4}}{{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}} e^{6}}\right )} - \frac {e^{5} x^{6}}{{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}}} - \frac {7}{3} \, d e^{4} x {\left (\frac {3 \, x^{2}}{{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {3}{2}} e^{2}} - \frac {2 \, d^{2}}{{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {3}{2}} e^{4}}\right )} + \frac {27 \, d^{2} e^{3} x^{4}}{{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}}} + \frac {35 \, d^{3} e^{2} x^{3}}{2 \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}}} - \frac {73 \, d^{4} e x^{2}}{3 \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}}} - \frac {61 \, d^{5} x}{10 \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}}} + \frac {167 \, d^{6}}{15 \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}} e} + \frac {127 \, d^{3} x}{30 \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {3}{2}}} + \frac {22 \, d x}{15 \, \sqrt {-e^{2} x^{2} + d^{2}}} - \frac {7 \, d \arcsin \left (\frac {e^{2} x}{d \sqrt {e^{2}}}\right )}{\sqrt {e^{2}}} \]
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Time = 0.30 (sec) , antiderivative size = 205, normalized size of antiderivative = 1.49 \[ \int \frac {(d+e x)^7}{\left (d^2-e^2 x^2\right )^{7/2}} \, dx=-\frac {7 \, d \arcsin \left (\frac {e x}{d}\right ) \mathrm {sgn}\left (d\right ) \mathrm {sgn}\left (e\right )}{{\left | e \right |}} + \frac {\sqrt {-e^{2} x^{2} + d^{2}}}{e} + \frac {16 \, {\left (19 \, d - \frac {80 \, {\left (d e + \sqrt {-e^{2} x^{2} + d^{2}} {\left | e \right |}\right )} d}{e^{2} x} + \frac {130 \, {\left (d e + \sqrt {-e^{2} x^{2} + d^{2}} {\left | e \right |}\right )}^{2} d}{e^{4} x^{2}} - \frac {60 \, {\left (d e + \sqrt {-e^{2} x^{2} + d^{2}} {\left | e \right |}\right )}^{3} d}{e^{6} x^{3}} + \frac {15 \, {\left (d e + \sqrt {-e^{2} x^{2} + d^{2}} {\left | e \right |}\right )}^{4} d}{e^{8} x^{4}}\right )}}{15 \, {\left (\frac {d e + \sqrt {-e^{2} x^{2} + d^{2}} {\left | e \right |}}{e^{2} x} - 1\right )}^{5} {\left | e \right |}} \]
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Timed out. \[ \int \frac {(d+e x)^7}{\left (d^2-e^2 x^2\right )^{7/2}} \, dx=\int \frac {{\left (d+e\,x\right )}^7}{{\left (d^2-e^2\,x^2\right )}^{7/2}} \,d x \]
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